CSEET logical reasoning - Calendar
- Artha Institute of Management
- Oct 13
- 4 min read
The Calendar topic in Logical Reasoning is all about the concept of Odd Days and the repetition of the 7-day week cycle.
Here are 15 multiple-choice questions (MCQs) on Calendars for your CSEET preparation, along with answers and detailed explanations.
CSEET Calendar Logical Reasoning MCQs
Type 1: Day-to-Day/Year-to-Year Change
Explanations for Type 1
A1: Year 2023 is an Ordinary Year (365 days) which has 1 odd day (365/7, Remainder=1). The day advances by 1. Sunday + 1 = Monday.
A2: Year 2012 is a Leap Year (366 days), which has 2 odd days. When moving from an Ordinary Year to a Leap Year, and February 29 is crossed (April 5, 2011 to April 5, 2012), the day advances by 2. Tuesday + 2 = Thursday.
A3: Thursday + 5 days: F, S, Su, M, Tu, W. Wait, Thursday + 5 is Tuesday. 75/7=5 odd days. T + 5: F, S, Su, M, Tu. Answer is Tuesday, not Saturday. Let me check the provided answer. 75/7=10 rem 5. Thursday +5 days is Tuesday.
A4: Year 2004 is a Leap Year. When moving backward from 2005 to 2004, the date October 10 crosses February 29 of 2004. So, we subtract 2 days. Monday - 2 days = Saturday.
A5: Year 2024 is a Leap Year (2 odd days). Since we are moving from Jan 1, 2024, to Jan 1, 2025, we cross February 29, 2024. The day advances by 2 days. Monday + 2 = Wednesday.
Type 2: Finding Day of the Week within the Same Year
Explanations for Type 2
A6: Number of days between Jan 12 and Jan 30 is 30−12=18 days. Odd days in 18=718=2 weeks and 4 odd days. Monday + 4 days = Friday.
A7: We calculate the odd days between the dates:
March: 31−10=21 days (0 odd days)
April: 30 days (2 odd days)
May: 20 days (20/7 = 6 odd days)
Total odd days = 0+2+6=8. 8/7=1 odd day. Friday + 1 day = Saturday.
A8: If 3rd is Tuesday, the next Tuesday is on 3+7=10, then 10+7=17, then 17+7=24. So, the 24th is a Tuesday. Therefore, the 25th is a Wednesday.
A9:
July: 31 days (3 odd days)
August: 31 days (3 odd days)
September: 30 days (2 odd days)
Total odd days = 3+3+2=8. 8/7=1 odd day.
A10: Same calendar means 0 odd days between the start of the first month and the start of the second month.
Apr to July: April (30 days → 2 OD) + May (31 days → 3 OD) + June (30 days → 2 OD) = 2+3+2=7 odd days. 77=0 odd days.
Type 3: Century and Day of the Week Calculations
Explanations for Type 3
A11: Odd days in centuries: 100 years = 5 odd days. 200 years = 10→3 odd days. 300 years = 15→1 odd day. 400 years = 20+1→0 odd days.
A12: A year is a leap year if divisible by 4. A century year (ending in '00') is a leap year only if it is divisible by 400. 1900 is not divisible by 400.
A13: The number of odd days for 100, 200, 300, and 400 years are 5, 3, 1, and 0, which correspond to Friday, Wednesday, Monday, and Sunday. Thus, a century can only end on these four days. It can NOT end on Tuesday (2), Thursday (4), or Saturday (6).
A14: The calendar of a normal year repeats after a total of 6 or 11 odd days have accumulated.
2007 (1 OD)
2008 (2 OD - Leap Year)
2009 (1 OD)
2010 (1 OD)
2011 (1 OD)
2012 (2 OD - Leap Year)
2013 (1 OD)
Sum of OD till 2012 (6 years) = 1+2+1+1+1+2=8→1 OD.
Sum of OD till 2017 (10 years) = 1+2+1+1+1+2+1+1+1+2=13→6 OD.
Sum of OD till 2018 (11 years) = 13+1=14→0 odd days. The calendar repeats in 2018 (after 6+5=11years).
A15: We calculate the odd days from Jan 1 to Mar 2, 2005:
January: 31 days (3 odd days)
February: 28 days (0 odd days) (2005 is ordinary)
March: 2 days (2 odd days)
Total odd days = 3+0+2=5 odd days.
Saturday + 5 days = Sunday, Monday, Tuesday, Wednesday, Thursday.
The day is Wednesday.
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